题目内容
用递等式计算
6÷
|
(1000-0.16×1900)÷96 |
| |||||||||||||
(
|
|
(1)6÷
-
÷6,
=10-
,
=9
;
(2)(1000-0.16×1900)÷96,
=÷96,
=696÷96,
=7.25;
(3)
×[
÷(
-
)],
=
×[
÷
],
=
×
,
=4;
(4)(
+
)÷(
-
),
=
÷
,
=
;
(5)
×[1÷(
+
)],
=
×[1÷
],
=
×
,
=
.
| 3 |
| 5 |
| 3 |
| 5 |
=10-
| 1 |
| 10 |
=9
| 9 |
| 10 |
(2)(1000-0.16×1900)÷96,
=÷96,
=696÷96,
=7.25;
(3)
| 3 |
| 8 |
| 8 |
| 9 |
| 5 |
| 6 |
| 3 |
| 4 |
=
| 3 |
| 8 |
| 8 |
| 9 |
| 1 |
| 12 |
=
| 3 |
| 8 |
| 32 |
| 3 |
=4;
(4)(
| 5 |
| 8 |
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 2 |
=
| 7 |
| 8 |
| 1 |
| 6 |
=
| 21 |
| 4 |
(5)
| 5 |
| 8 |
| 3 |
| 4 |
| 1 |
| 3 |
=
| 5 |
| 8 |
| 13 |
| 12 |
=
| 5 |
| 8 |
| 12 |
| 13 |
=
| 15 |
| 26 |
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