题目内容
计算
(1)57.5-14.25-15
(2)
×102.31+40
×102.31
(3)24×(
+
-
)
(4)
÷〔
×(
+
)〕
(1)57.5-14.25-15
| 3 |
| 4 |
(2)
| 1 |
| 7 |
| 6 |
| 7 |
(3)24×(
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 6 |
(4)
| 2 |
| 5 |
| 5 |
| 8 |
| 9 |
| 10 |
| 1 |
| 6 |
分析:(1)把题干中的分数化为小数,再运用减法的性质解答,
(2)(3)运用乘法分配律解答,
(4)依据四则运算计算方法,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右的顺序计算,有括号先算括号里面的解答.
(2)(3)运用乘法分配律解答,
(4)依据四则运算计算方法,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右的顺序计算,有括号先算括号里面的解答.
解答:解:(1)57.5-14.25-15
,
=57.5-14.25-15.75,
=57.5-(14.25+15.75),
=57.5-30,
=27.5;
(2)
×102.31+40
×102.31,
=(
+40
)×102.31,
=41×102.31,
=(40+1)×102.31,
=40×102.31+1×102.31,
=4092.4+102.31,
=4194.71;
(3)24×(
+
-
),
=24×
+24×
-24×
,
=6+16-4,
=22-4,
=18;
(4)
÷〔
×(
+
)〕,
=
÷[
×
],
=
÷
,
=
.
| 3 |
| 4 |
=57.5-14.25-15.75,
=57.5-(14.25+15.75),
=57.5-30,
=27.5;
(2)
| 1 |
| 7 |
| 6 |
| 7 |
=(
| 1 |
| 7 |
| 6 |
| 7 |
=41×102.31,
=(40+1)×102.31,
=40×102.31+1×102.31,
=4092.4+102.31,
=4194.71;
(3)24×(
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 6 |
=24×
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 6 |
=6+16-4,
=22-4,
=18;
(4)
| 2 |
| 5 |
| 5 |
| 8 |
| 9 |
| 10 |
| 1 |
| 6 |
=
| 2 |
| 5 |
| 5 |
| 8 |
| 32 |
| 30 |
=
| 2 |
| 5 |
| 2 |
| 3 |
=
| 3 |
| 5 |
点评:本题主要考查学生正确的选择运算方法和运算定律、性质进行简算的能力.
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