题目内容
3.14×
|
18.7-3.375-6.625 | 306×15-2080 | ||||||||||||||||||||||
|
(
|
|
分析:(1)运用乘法分配律的逆运算简算;
(2)运用减法的性质简算;
(3)把306看作300+6,运用乘法分配律简算,得4500+90-2080,把2080看作200+80,用加法交换律与结合律简算;
(4)先算
÷
=
,运用加法结合律,得
+(
-
),计算即可;
(5)先算括号内的乘法,再算括号内的加法,最后算括号外的除法,注意约分;
(6)先算小括号内的,再算中括号内的除法,再算中括号内的减法,最后算括号外的乘法.
(2)运用减法的性质简算;
(3)把306看作300+6,运用乘法分配律简算,得4500+90-2080,把2080看作200+80,用加法交换律与结合律简算;
(4)先算
| 1 |
| 3 |
| 1 |
| 2 |
| 2 |
| 3 |
| 9 |
| 10 |
| 5 |
| 6 |
| 2 |
| 3 |
(5)先算括号内的乘法,再算括号内的加法,最后算括号外的除法,注意约分;
(6)先算小括号内的,再算中括号内的除法,再算中括号内的减法,最后算括号外的乘法.
解答:解:(1)3.14×
+3.14×
,
=3.14×(
+
),
=3.14×1,
=3.14;
(2)18.7-3.375-6.625,
=18.7-(3.375+6.625),
=18.7-10,
=8.7;
(3)306×15-2080,
=(300+6)×15-2080,
=300×15+6×15-2080,
=4500+90-2080,
=4500+90-(2000+80),
=4500-2000+(90-80),
=2500+10,
=2510;
(4)
-
÷
+
,
=
-
×2+
,
=
-
+
,
=
+(
-
),
=
+
,
=
;
(5)(
+
×
)÷
,
=(
+
)×
,
=
×
,
=5;
(6)
×[7-4÷(
+
)],
=
×[7-4÷
],
=
×[7-4×
],
=
×[7-5],
=
×2,
=
.
| 1 |
| 5 |
| 4 |
| 5 |
=3.14×(
| 1 |
| 5 |
| 4 |
| 5 |
=3.14×1,
=3.14;
(2)18.7-3.375-6.625,
=18.7-(3.375+6.625),
=18.7-10,
=8.7;
(3)306×15-2080,
=(300+6)×15-2080,
=300×15+6×15-2080,
=4500+90-2080,
=4500+90-(2000+80),
=4500-2000+(90-80),
=2500+10,
=2510;
(4)
| 9 |
| 10 |
| 1 |
| 3 |
| 1 |
| 2 |
| 5 |
| 6 |
=
| 9 |
| 10 |
| 1 |
| 3 |
| 5 |
| 6 |
=
| 9 |
| 10 |
| 2 |
| 3 |
| 5 |
| 6 |
=
| 9 |
| 10 |
| 5 |
| 6 |
| 2 |
| 3 |
=
| 9 |
| 10 |
| 1 |
| 6 |
=
| 16 |
| 15 |
(5)(
| 7 |
| 9 |
| 2 |
| 3 |
| 5 |
| 6 |
| 4 |
| 15 |
=(
| 7 |
| 9 |
| 5 |
| 9 |
| 15 |
| 4 |
=
| 4 |
| 3 |
| 15 |
| 4 |
=5;
(6)
| 4 |
| 5 |
| 2 |
| 15 |
| 2 |
| 3 |
=
| 4 |
| 5 |
| 4 |
| 5 |
=
| 4 |
| 5 |
| 5 |
| 4 |
=
| 4 |
| 5 |
=
| 4 |
| 5 |
=
| 8 |
| 5 |
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用所学定律进行简便计算.
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