题目内容
列式计算,能简算的简算
(1)2010-4848÷9.6×2.4
(2)(
-
×
)÷
(3)
×[
-(
-
)]
(4)(
+
+
)×12+
(5)已知18+[
×1.25+(
+
(1)2010-4848÷9.6×2.4
(2)(
| 3 |
| 4 |
| 3 |
| 4 |
| 2 |
| 5 |
| 1 |
| 5 |
(3)
| 8 |
| 9 |
| 3 |
| 4 |
| 15 |
| 16 |
| 3 |
| 4 |
(4)(
| 2 |
| 3 |
| 5 |
| 12 |
| 1 |
| 19 |
| 7 |
| 19 |
(5)已知18+[
| 2 |
| 5 |
| 1 |
| 2 |
0.625
0.625
×12]÷0.125=86,求出横线上应填的数.分析:(1)(2)(3)依据四则运算顺序解答,
(4)先运用乘法分配律算出(
+
+
)×12=8+5+
,再运用加法结合律解答,
(5)设要求的数是x,再依据等式性质解方程求解.
(4)先运用乘法分配律算出(
| 2 |
| 3 |
| 5 |
| 12 |
| 1 |
| 19 |
| 12 |
| 19 |
(5)设要求的数是x,再依据等式性质解方程求解.
解答:解:(1)2010-4848÷9.6×2.4,
=2010-505×2.4,
=2010-1212,
=798;
(2)(
-
×
)÷
,
=(
-
)÷
,
=
÷
,
=2.25;
(3)
×[
-(
-
)],
=
×[
-
],
=
×
,
=0.5;
(4)(
+
+
)×12+
,
=
×12+
×12+
×12+
,
=8+5+(
+
),
=13+1,
=14;
(5)设要求的数是x,
18+[
×1.25+(
+x×12)]÷0.125=86,
18+[
×1.25+
+12x]÷0.125=86,
18+[1+12x]÷0.125=86,
18+8+96x=86,
26+96x-26=86-26,
96x÷96=60÷96,
x=0.625.
答:要求的数是0.625,
故答案为:798,2.25,0.5,14,0.625.
=2010-505×2.4,
=2010-1212,
=798;
(2)(
| 3 |
| 4 |
| 3 |
| 4 |
| 2 |
| 5 |
| 1 |
| 5 |
=(
| 3 |
| 4 |
| 3 |
| 10 |
| 1 |
| 5 |
=
| 9 |
| 20 |
| 1 |
| 5 |
=2.25;
(3)
| 8 |
| 9 |
| 3 |
| 4 |
| 15 |
| 16 |
| 3 |
| 4 |
=
| 8 |
| 9 |
| 3 |
| 4 |
| 3 |
| 16 |
=
| 8 |
| 9 |
| 9 |
| 16 |
=0.5;
(4)(
| 2 |
| 3 |
| 5 |
| 12 |
| 1 |
| 19 |
| 7 |
| 19 |
=
| 2 |
| 3 |
| 5 |
| 12 |
| 1 |
| 19 |
| 7 |
| 19 |
=8+5+(
| 12 |
| 19 |
| 7 |
| 19 |
=13+1,
=14;
(5)设要求的数是x,
18+[
| 2 |
| 5 |
| 1 |
| 2 |
18+[
| 2 |
| 5 |
| 1 |
| 2 |
18+[1+12x]÷0.125=86,
18+8+96x=86,
26+96x-26=86-26,
96x÷96=60÷96,
x=0.625.
答:要求的数是0.625,
故答案为:798,2.25,0.5,14,0.625.
点评:(1)(2)(3)考查学生对于四则运算计算方法掌握,
(4)考察运用乘法分配律以及加法结合律能力,
(5)考查依据等式性质解方程能力.
(4)考察运用乘法分配律以及加法结合律能力,
(5)考查依据等式性质解方程能力.
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