题目内容
列式计算.
(1)用160的20%的
与12的差去除16个
,商是多少?
(2)甲数是40,比乙数的30%还多10,求乙数.
(1)用160的20%的
| 1 |
| 2 |
| 3 |
| 4 |
(2)甲数是40,比乙数的30%还多10,求乙数.
(1)
×16÷(160×20%×
-12),
=12÷(16-12),
=12÷4,
=3.
答:商是3.
(2)(40-10)÷30%,
=30÷0.3,
=100.
答:乙数是100.
| 3 |
| 4 |
| 1 |
| 2 |
=12÷(16-12),
=12÷4,
=3.
答:商是3.
(2)(40-10)÷30%,
=30÷0.3,
=100.
答:乙数是100.
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