题目内容
x÷4
|
20
|
7
|
分析:(1)原式变为x÷
=
,根据等式的性质,两边同乘
即可;
(2)原式变为5x-16=31,根据等式的性质,两边同除以5即可;
(3)原式变为(7
-5
)x=12.6,即
x=12.6,根据等式的性质,两边同乘
即可.
| 9 |
| 2 |
| 9 |
| 2 |
| 9 |
| 2 |
(2)原式变为5x-16=31,根据等式的性质,两边同除以5即可;
(3)原式变为(7
| 1 |
| 5 |
| 2 |
| 5 |
| 9 |
| 5 |
| 5 |
| 9 |
解答:解:(1)x÷4
=4
,
x÷
=
,
x÷
×
=
×
,
x=
;
(2)20
+5x-4
=31,
5x-16=31,
5x-16+16=31+16,
5x=47,
5x÷5=47÷5,
x=9.4;
(3)7
x-5
x=12.6,
(7
-5
)x=12.6,
x=12.6,
x×
=12.6×
,
x=7.
| 1 |
| 2 |
| 1 |
| 2 |
x÷
| 9 |
| 2 |
| 9 |
| 2 |
x÷
| 9 |
| 2 |
| 9 |
| 2 |
| 9 |
| 2 |
| 9 |
| 2 |
x=
| 81 |
| 4 |
(2)20
| 1 |
| 2 |
| 1 |
| 2 |
5x-16=31,
5x-16+16=31+16,
5x=47,
5x÷5=47÷5,
x=9.4;
(3)7
| 1 |
| 5 |
| 2 |
| 5 |
(7
| 1 |
| 5 |
| 2 |
| 5 |
| 9 |
| 5 |
| 9 |
| 5 |
| 5 |
| 9 |
| 5 |
| 9 |
x=7.
点评:此题考查了根据等式的性质解方程,即等式两边同加上或同减去、同乘上或同除以同一个数(0除外),两边仍相等.
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