题目内容
简便计算:
×0.65+0.35×0.8
99×
×6+
×17.
| 4 |
| 5 |
99×
| 97 |
| 98 |
| 8 |
| 25 |
| 6 |
| 25 |
分析:(1)把
化成小数是0.8,再利用乘法的分配律作答;
(2)将99写成98+1,再利用乘法的分配律作答;
(3)将
×6,中的8和6交换位置,即为
×8,再利用乘法的分配律作答.
| 4 |
| 5 |
(2)将99写成98+1,再利用乘法的分配律作答;
(3)将
| 8 |
| 25 |
| 6 |
| 25 |
解答:解:(1)
×0.65+0.35×0.8,
=0.8×0.65+0.35×0.8,
=0.8×(0.65+0.35),
=0.8×1,
=0.8,
(2)99×
,
=(98+1)×
,
=98×
+1×
,
=97+
,
=97
;
(3)
×6+
×17,
=
×8+
×17,
=
×(8+17),
=
×25,
=6.
| 4 |
| 5 |
=0.8×0.65+0.35×0.8,
=0.8×(0.65+0.35),
=0.8×1,
=0.8,
(2)99×
| 97 |
| 98 |
=(98+1)×
| 97 |
| 98 |
=98×
| 97 |
| 98 |
| 97 |
| 98 |
=97+
| 97 |
| 98 |
=97
| 97 |
| 98 |
(3)
| 8 |
| 25 |
| 6 |
| 25 |
=
| 6 |
| 25 |
| 6 |
| 25 |
=
| 6 |
| 25 |
=
| 6 |
| 25 |
=6.
点评:此题主要考查了乘法的分配律的(两个数相加或相减)再乘另一个数,等于把这个数分别同两个加数或减数相乘,再把两个积相加或相减,得数不变,用字母表示:a(b+c)=ab+ac的应用.
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