题目内容
计算下面各题.
[1-(
+
)]÷
×
÷(
-
)
+(
-
)÷
12÷[(
-
)×6].
[1-(
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
| 1 |
| 6 |
| 2 |
| 3 |
| 4 |
| 5 |
| 8 |
| 15 |
| 15 |
| 16 |
| 7 |
| 16 |
| 1 |
| 4 |
| 1 |
| 2 |
| 5 |
| 6 |
| 1 |
| 3 |
分析:(1)先算小括号里面的加法,再算中括号里面的减法,最后算括号外的除法;
(2)先算小括号里面的减法,再算括号外的乘法,最后算括号外的除法;
(3)先算小括号里面的减法,再算括号外的除法,最后算加法;
(4)先算小括号里面的减法,再算中括号里面的乘法,最后算括号外的除法.
(2)先算小括号里面的减法,再算括号外的乘法,最后算括号外的除法;
(3)先算小括号里面的减法,再算括号外的除法,最后算加法;
(4)先算小括号里面的减法,再算中括号里面的乘法,最后算括号外的除法.
解答:解:(1)[1-(
+
)]÷
,
=[1-
]÷
,
=
÷
,
=
;
(2)
×
÷(
-
),
=
×
÷
,
=
×
,
=
;
(3)
+(
-
)÷
,
=
+
÷
,
=
+
,
=
;
(4)12÷[(
-
)×6],
=12÷[
×6],
=12÷3,
=4.
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
=[1-
| 5 |
| 8 |
| 1 |
| 4 |
=
| 3 |
| 8 |
| 1 |
| 4 |
=
| 3 |
| 2 |
(2)
| 1 |
| 6 |
| 2 |
| 3 |
| 4 |
| 5 |
| 8 |
| 15 |
=
| 1 |
| 6 |
| 2 |
| 3 |
| 4 |
| 15 |
=
| 1 |
| 9 |
| 15 |
| 4 |
=
| 5 |
| 12 |
(3)
| 15 |
| 16 |
| 7 |
| 16 |
| 1 |
| 4 |
| 1 |
| 2 |
=
| 15 |
| 16 |
| 3 |
| 16 |
| 1 |
| 2 |
=
| 15 |
| 16 |
| 6 |
| 16 |
=
| 21 |
| 16 |
(4)12÷[(
| 5 |
| 6 |
| 1 |
| 3 |
=12÷[
| 1 |
| 2 |
=12÷3,
=4.
点评:1.一个算式里,如果含有两级运算,要先做第二级运算,后做第一级运算.
2.一个算式里,如果有括号,要先算小括号里的,再算中括号里面的.
2.一个算式里,如果有括号,要先算小括号里的,再算中括号里面的.
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