题目内容
脱式计算 (带☆的要简算)
|
☆
| ||||||||||||||||
☆5-2
|
☆
| ||||||||||||||||
| ☆25×32×125. |
分析:(1)先算小括号里面的乘法,再算除法,最后算括号外面的乘法;
(2)根据乘法分配律进行计算;
(3)根据连减的性质进行计算;
(4)根据乘法分配律进行计算;
(5)根据乘法交换律和结合律进行计算.
(2)根据乘法分配律进行计算;
(3)根据连减的性质进行计算;
(4)根据乘法分配律进行计算;
(5)根据乘法交换律和结合律进行计算.
解答:解:(1)
×[
÷(
×
)],
=
×[
÷
],
=
×
,
=
;
(2)
×
+
×
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(3)5-2
-1
,
=5-(2
+1
),
=5-4,
=1;
(4)
×2002,
=
×(2001+1),
=
×2001+
×1,
=2000+
,
=2000
,
(5)25×32×125,
=25×(4×8)×125,
=(25×4)×(8×125),
=100×1000,
=100000.
| 1 |
| 8 |
| 1 |
| 2 |
| 3 |
| 5 |
| 10 |
| 9 |
=
| 1 |
| 8 |
| 1 |
| 2 |
| 2 |
| 3 |
=
| 1 |
| 8 |
| 3 |
| 4 |
=
| 3 |
| 32 |
(2)
| 7 |
| 11 |
| 8 |
| 25 |
| 3 |
| 11 |
| 7 |
| 25 |
=
| 8 |
| 11 |
| 7 |
| 25 |
| 3 |
| 11 |
| 7 |
| 25 |
=(
| 8 |
| 11 |
| 3 |
| 11 |
| 7 |
| 25 |
=1×
| 7 |
| 25 |
=
| 7 |
| 25 |
(3)5-2
| 14 |
| 17 |
| 3 |
| 17 |
=5-(2
| 14 |
| 17 |
| 3 |
| 17 |
=5-4,
=1;
(4)
| 2000 |
| 2001 |
=
| 2000 |
| 2001 |
=
| 2000 |
| 2001 |
| 2000 |
| 2001 |
=2000+
| 2000 |
| 2001 |
=2000
| 2000 |
| 2001 |
(5)25×32×125,
=25×(4×8)×125,
=(25×4)×(8×125),
=100×1000,
=100000.
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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