题目内容
计算(能简算的要简算)
:
:
×
÷
÷
×
(
-
×
)÷
.
| 3 |
| 8 |
| 1 |
| 4 |
| 4 |
| 7 |
| 5 |
| 4 |
| 7 |
| 6 |
| 8 |
| 3 |
| 17 |
| 15 |
| 51 |
| 7 |
| 15 |
| 14 |
(
| 2 |
| 9 |
| 2 |
| 7 |
| 7 |
| 9 |
| 1 |
| 6 |
分析:根据求比值的方法,用比的前项除以后项即得比值;
最后一道题先算括号里面的乘法,再算括号里面的减法,最后算括号外面的除法;
其它按照分数乘除法的计算方法计算得解.
最后一道题先算括号里面的乘法,再算括号里面的减法,最后算括号外面的除法;
其它按照分数乘除法的计算方法计算得解.
解答:解:(1)
:
,
=
÷
,
=
;
(2)
:
×
÷
,
=
×
×
×
,
=
;
(3)
÷
×
,
=
×
×
,
=
;
(4)(
-
×
)÷
,
=(
-
)÷
,
=0.
| 3 |
| 8 |
| 1 |
| 4 |
=
| 3 |
| 8 |
| 1 |
| 4 |
=
| 3 |
| 2 |
(2)
| 4 |
| 7 |
| 5 |
| 4 |
| 7 |
| 6 |
| 8 |
| 3 |
=
| 4 |
| 7 |
| 4 |
| 5 |
| 7 |
| 6 |
| 3 |
| 8 |
=
| 1 |
| 5 |
(3)
| 17 |
| 15 |
| 51 |
| 7 |
| 15 |
| 14 |
=
| 17 |
| 15 |
| 7 |
| 51 |
| 15 |
| 14 |
=
| 1 |
| 6 |
(4)(
| 2 |
| 9 |
| 2 |
| 7 |
| 7 |
| 9 |
| 1 |
| 6 |
=(
| 2 |
| 9 |
| 2 |
| 9 |
| 1 |
| 6 |
=0.
点评:解决此题关键是把算式中的除以一个数,改成乘这个数的倒数,进而先把分子和分母交叉约分,再计算得解.
练习册系列答案
相关题目