题目内容
解方程.
x÷
=
x+
x=36
x+
=
.
| 2 |
| 3 |
| 4 |
| 5 |
| 3 |
| 8 |
x+
| 1 |
| 5 |
| 1 |
| 3 |
| 2 |
| 3 |
| 6 |
| 9 |
分析:(1)先根据等式的性质,方程两边都乘
,然后方程两边再都除以
即可.
(2)先算出方程左边是多少个x,方向两边再除以多少即可.
(3)根据等式的基本性质,方向两边都减
,然后方程两边都除以
即可.
| 4 |
| 5 |
| 2 |
| 3 |
(2)先算出方程左边是多少个x,方向两边再除以多少即可.
(3)根据等式的基本性质,方向两边都减
| 2 |
| 3 |
| 1 |
| 3 |
解答:解:(1)
x÷
=
x÷
×
=
×
x=
x÷
=
÷
x=
;
(2)x+
x=36
x=36
x÷
=36÷
x=30;
(3)
x+
=
x+
-
=
-
x=0
x÷
=0÷
x=0.
| 2 |
| 3 |
| 4 |
| 5 |
| 3 |
| 8 |
| 2 |
| 3 |
| 4 |
| 5 |
| 4 |
| 5 |
| 3 |
| 8 |
| 4 |
| 5 |
| 2 |
| 3 |
| 3 |
| 10 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 10 |
| 2 |
| 3 |
x=
| 9 |
| 20 |
(2)x+
| 1 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
x=30;
(3)
| 1 |
| 3 |
| 2 |
| 3 |
| 6 |
| 9 |
| 1 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 6 |
| 9 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
x=0.
点评:本题是考查解方程,属于基础知识.解方程时要注意书写格式,求出方程的解后要养成口头验算的习惯.
练习册系列答案
相关题目