题目内容
计算下列各题:
(1)10.875×201+201×
-201 (2)2.4×(
+1
)÷(4.5-
)
(3)4
-3
+8.125-42×(
-
) (4)2008÷2008
.
(1)10.875×201+201×
| 1 |
| 8 |
| 7 |
| 12 |
| 5 |
| 6 |
| 3 |
| 5 |
(3)4
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 6 |
| 1 |
| 7 |
| 2008 |
| 2009 |
分析:(1)把201看作201×1,运用乘法分配律的逆运算简算;
(2)按运算顺序计算,先算括号内的,然后从左向右依次计算;
(3)前三项把分数化为小数计算,在计算42×(
-
)时,运用乘法分配律简算;
(4)把除数由带分数化为假分数,分子不必算出来,其分子部分2008×(2009+1)=2008×2010中的2008,可与被除数中的2008约分.
(2)按运算顺序计算,先算括号内的,然后从左向右依次计算;
(3)前三项把分数化为小数计算,在计算42×(
| 1 |
| 6 |
| 1 |
| 7 |
(4)把除数由带分数化为假分数,分子不必算出来,其分子部分2008×(2009+1)=2008×2010中的2008,可与被除数中的2008约分.
解答:解:(1)10.875×201+201×
-201,
=(10.875+
-1)×201,
=(10.875+0.125-1)×201,
=10×201,
=2010;
(2)2.4×(
+1
)÷(4.5-
),
=2.4×
÷(4
-
),
=5.8÷
,
=
×
,
=
;
(3)4
-3
+8.125-42×(
-
),
=(4.25-3.375+8.125)-42×
+42×
,
=9-42×
+42×
,
=9-7+6,
=8;
(4)2008÷2008
,
=2008÷
,
=2008÷
,
=2008×
,
=
.
| 1 |
| 8 |
=(10.875+
| 1 |
| 8 |
=(10.875+0.125-1)×201,
=10×201,
=2010;
(2)2.4×(
| 7 |
| 12 |
| 5 |
| 6 |
| 3 |
| 5 |
=2.4×
| 29 |
| 12 |
| 1 |
| 2 |
| 3 |
| 5 |
=5.8÷
| 39 |
| 10 |
=
| 29 |
| 5 |
| 10 |
| 39 |
=
| 58 |
| 39 |
(3)4
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 6 |
| 1 |
| 7 |
=(4.25-3.375+8.125)-42×
| 1 |
| 6 |
| 1 |
| 7 |
=9-42×
| 1 |
| 6 |
| 1 |
| 7 |
=9-7+6,
=8;
(4)2008÷2008
| 2008 |
| 2009 |
=2008÷
| 2008×2009+2008 |
| 2009 |
=2008÷
| 2008×(2009+1) |
| 2009 |
=2008×
| 2009 |
| 2008×2010 |
=
| 2009 |
| 2010 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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