题目内容
怎样算简便就怎样算
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8×(
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分析:(1)先算除法,再运用减法性质解答,
(2)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序解答,
(3)(4)运用乘法分配律解答.
(2)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序解答,
(3)(4)运用乘法分配律解答.
解答:解:(1)
-
÷
-
=
-
-
=
-(
+
)
=
-1
=1
;
(2)
÷[
×(
-
)]
=
÷[
×
]
=
÷
=2
;
(3)8×(
-
)×13
=8×
×13-8×
×13
=91-24
=67;
(4)
×
+
÷8+12.5%
=
×(
+
+1)
=
×2
=
.
| 18 |
| 7 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 3 |
=
| 18 |
| 7 |
| 2 |
| 3 |
| 1 |
| 3 |
=
| 18 |
| 7 |
| 2 |
| 3 |
| 1 |
| 3 |
=
| 18 |
| 7 |
=1
| 4 |
| 7 |
(2)
| 2 |
| 3 |
| 9 |
| 14 |
| 5 |
| 6 |
| 4 |
| 9 |
=
| 2 |
| 3 |
| 9 |
| 14 |
| 7 |
| 18 |
=
| 2 |
| 3 |
| 1 |
| 4 |
=2
| 2 |
| 3 |
(3)8×(
| 7 |
| 8 |
| 3 |
| 13 |
=8×
| 7 |
| 8 |
| 3 |
| 13 |
=91-24
=67;
(4)
| 1 |
| 8 |
| 7 |
| 11 |
| 4 |
| 11 |
=
| 1 |
| 8 |
| 7 |
| 11 |
| 4 |
| 11 |
=
| 1 |
| 8 |
=
| 1 |
| 4 |
点评:本题主要考查学生依据四则计算方法,以及正确运用乘法分配律解决问题的能力.
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