题目内容
计算
(1)[670
×72+251
×(46
+1
)]÷30-11
(2)(
+0.25)×1.44÷[(8
-75%÷
)÷29]
(3)1-(
×
)÷[(2-
×58%)+2
]
(4)
×(
×9-
)÷(2
+1
)×(2011-2)
(1)[670
| 1 |
| 3 |
| 3 |
| 8 |
| 3 |
| 8 |
| 5 |
| 8 |
(2)(
| 1 |
| 3 |
| 1 |
| 3 |
| 3 |
| 14 |
(3)1-(
| 78 |
| 65 |
| 2 |
| 3 |
| 18 |
| 29 |
| 1 |
| 5 |
(4)
| 13 |
| 28 |
| 3 |
| 13 |
| 11 |
| 13 |
| 3 |
| 13 |
| 10 |
| 13 |
分析:(1)先算小括号里面的加法,再同时运算中括号里面的乘法,然后算中括号里面的加法,再算括号外的除法,最后算减法;
(2)先算第一个小括号里面的加法和第二个小括号里面的除法,然后算第二个小括号里面的减法,接着算中括号里面的除法,再运用乘法结合律简算括号外的计算;
(3)同时运算两个小括号里面的乘法,然后算第二个小括号里面的减法,再算中括号里面的加法,最后算括号外的减法;
(4)先算第一个小括号里面的乘法,然后同时运算三个小括号里面的加减法,再把括号外的乘除法按照从左到右的顺序计算.
(2)先算第一个小括号里面的加法和第二个小括号里面的除法,然后算第二个小括号里面的减法,接着算中括号里面的除法,再运用乘法结合律简算括号外的计算;
(3)同时运算两个小括号里面的乘法,然后算第二个小括号里面的减法,再算中括号里面的加法,最后算括号外的减法;
(4)先算第一个小括号里面的乘法,然后同时运算三个小括号里面的加减法,再把括号外的乘除法按照从左到右的顺序计算.
解答:解:(1)[670
×72+251
×(46
+1
)]÷30-11,
=[670
×72+251
×48]÷30-11,
=(48264+12066)÷30-11,
=60330÷30-11,
=2011-11,
=2000;
(2)(
+0.25)×1.44÷[(8
-75%÷
)÷29],
=
×1.44÷[(8
-
)÷29],
=
×1.44÷[
÷29],
=
×1.44÷
,
=
×6×1.44,
=
×1.44,
=5.04;
(3)1-(
×
)÷[(2-
×58%)+2
],
=1-
÷[(2-
)+2
],
=1-
÷[1
+2
],
=1-
÷
,
=1-
,
=
;
(4)
×(
×9-
)÷(2
+1
)×(2011-2),
=
×(
-
)÷(2
+1
)×(2011-2),
=
×
÷4×2009,
=
÷4×2009,
=
×2009,
=287.
| 1 |
| 3 |
| 3 |
| 8 |
| 3 |
| 8 |
| 5 |
| 8 |
=[670
| 1 |
| 3 |
| 3 |
| 8 |
=(48264+12066)÷30-11,
=60330÷30-11,
=2011-11,
=2000;
(2)(
| 1 |
| 3 |
| 1 |
| 3 |
| 3 |
| 14 |
=
| 7 |
| 12 |
| 1 |
| 3 |
| 7 |
| 2 |
=
| 7 |
| 12 |
| 29 |
| 6 |
=
| 7 |
| 12 |
| 1 |
| 6 |
=
| 7 |
| 12 |
=
| 7 |
| 2 |
=5.04;
(3)1-(
| 78 |
| 65 |
| 2 |
| 3 |
| 18 |
| 29 |
| 1 |
| 5 |
=1-
| 4 |
| 5 |
| 9 |
| 25 |
| 1 |
| 5 |
=1-
| 4 |
| 5 |
| 16 |
| 25 |
| 1 |
| 5 |
=1-
| 4 |
| 5 |
| 96 |
| 25 |
=1-
| 5 |
| 24 |
=
| 19 |
| 24 |
(4)
| 13 |
| 28 |
| 3 |
| 13 |
| 11 |
| 13 |
| 3 |
| 13 |
| 10 |
| 13 |
=
| 13 |
| 28 |
| 27 |
| 13 |
| 11 |
| 13 |
| 3 |
| 13 |
| 10 |
| 13 |
=
| 13 |
| 28 |
| 16 |
| 13 |
=
| 4 |
| 7 |
=
| 1 |
| 7 |
=287.
点评:本题考查了较复杂的四则混合运算,注意运算的顺序和运算法则,把结果化成最简分数.
练习册系列答案
相关题目