题目内容
能用简便方法的用简便方法.
(1)
+(
-
)÷2
(2)[
-(
-
)]×1
(3)20.07×1994-19.93×2007
(4)54÷[6.3-1
×(1
+
)]
(5)(1+
+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
+
).
(1)
| 7 |
| 10 |
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 4 |
(2)[
| 3 |
| 5 |
| 9 |
| 16 |
| 2 |
| 5 |
| 1 |
| 7 |
(3)20.07×1994-19.93×2007
(4)54÷[6.3-1
| 3 |
| 4 |
| 2 |
| 3 |
| 19 |
| 21 |
(5)(1+
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
(1)
| 7 |
| 10 |
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 4 |
=
| 7 |
| 10 |
| 11 |
| 20 |
| 3 |
| 4 |
=
| 7 |
| 10 |
| 1 |
| 5 |
=
| 9 |
| 10 |
(2)[
| 3 |
| 5 |
| 9 |
| 16 |
| 2 |
| 5 |
| 1 |
| 7 |
=[
| 3 |
| 5 |
| 9 |
| 16 |
| 2 |
| 5 |
| 1 |
| 7 |
=[
| 3 |
| 5 |
| 2 |
| 5 |
| 9 |
| 16 |
| 1 |
| 7 |
=[1-
| 9 |
| 16 |
| 1 |
| 7 |
=
| 7 |
| 16 |
| 1 |
| 7 |
=
| 1 |
| 2 |
(3)20.07×1994-19.93×2007,
=20.07×1994-1993×20.07,
=20.07×,
=20.07×1,
=20.07;
(4)54÷[6.3-1
| 3 |
| 4 |
| 2 |
| 3 |
| 19 |
| 21 |
=54÷[6.3-1
| 3 |
| 4 |
| 18 |
| 7 |
=54÷[6.3-4.5],
=54÷1.8,
=30;
(5)令
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
原式=(1+a)?b-(1+b)?a=b-a;
所以,(1+
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
=(
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
=
| 1 |
| 5 |
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