题目内容
| 脱式计算. (
|
| 24-(
| ||||||||||||||||||||||||
| (
|
|
考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)先算小括号里的减法,再算乘法;
(2)先算乘法,再算减法,最后算加法;
(3)先把除法转化为乘法,运用乘法分配律计算,再算加减;
(4)先把同分母分数相加,再计算;
(5)算第一个括号里的乘法,再算减法可得
-
×
=0,即可得答案;
(6)先算小括号里的加法,再算中括号的乘法,最后算除法.
(2)先算乘法,再算减法,最后算加法;
(3)先把除法转化为乘法,运用乘法分配律计算,再算加减;
(4)先把同分母分数相加,再计算;
(5)算第一个括号里的乘法,再算减法可得
| 7 |
| 5 |
| 7 |
| 4 |
| 4 |
| 5 |
(6)先算小括号里的加法,再算中括号的乘法,最后算除法.
解答:
解:(1)(
-
)×
=
×
=1;
(2)
×
+
-
=
+
-
=
+
=
;
(3)24-(
-
)÷
=24-(
-
)×
=24-
×
+
×
=24-1+
=29
;
(4)
+
+
+
=(
+
)+(
+
)
=20+11
=31;
(5)(
-
×
)÷(
-3)
=(
-
)÷(
-3)
=0;
(6)
÷[
×(
+
)
=
÷(
×
)
=
÷
=
.
| 7 |
| 2 |
| 13 |
| 6 |
| 3 |
| 4 |
=
| 4 |
| 3 |
| 3 |
| 4 |
=1;
(2)
| 12 |
| 5 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 5 |
=
| 4 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
=
| 3 |
| 5 |
| 2 |
| 3 |
=
| 19 |
| 15 |
(3)24-(
| 2 |
| 5 |
| 5 |
| 2 |
| 2 |
| 5 |
=24-(
| 2 |
| 5 |
| 5 |
| 2 |
| 5 |
| 2 |
=24-
| 2 |
| 5 |
| 5 |
| 2 |
| 5 |
| 2 |
| 5 |
| 2 |
=24-1+
| 25 |
| 4 |
=29
| 1 |
| 4 |
(4)
| 163 |
| 13 |
| 67 |
| 10 |
| 97 |
| 13 |
| 43 |
| 10 |
=(
| 163 |
| 13 |
| 97 |
| 13 |
| 67 |
| 10 |
| 43 |
| 10 |
=20+11
=31;
(5)(
| 7 |
| 5 |
| 7 |
| 4 |
| 4 |
| 5 |
| 47 |
| 15 |
=(
| 7 |
| 5 |
| 7 |
| 5 |
| 47 |
| 15 |
=0;
(6)
| 28 |
| 3 |
| 8 |
| 7 |
| 3 |
| 2 |
| 5 |
| 6 |
=
| 28 |
| 3 |
| 8 |
| 7 |
| 7 |
| 3 |
=
| 28 |
| 3 |
| 8 |
| 3 |
=
| 7 |
| 2 |
点评:本题主要考查了分数的四则混合运算,熟练掌握运算顺序是解题的关键,注意简便方法的运用.
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