题目内容
(2012?济源)
| 能用简便方法计算的要简算. 32×125%×0.25 |
12.5-0.625一
| ||||||||||||||
|
1÷[(
|
分析:(1)根据乘法交换律和结合律进行计算;
(2)根据连减的性质进行计算;
(3)中括号根据连减的性质进行计算,再算乘法;
(4)先算加法,再算中括号里面的除法,最后算括号外面的除法.
(2)根据连减的性质进行计算;
(3)中括号根据连减的性质进行计算,再算乘法;
(4)先算加法,再算中括号里面的除法,最后算括号外面的除法.
解答:解:
(1)32×125%×0.25,
=(4×8)×0.125×0.25,
=(8×0.125)×(4×0.25),
=1×1,
=1;
(2)12.5-0.625-
,
=12.5-(0.625+
),
=12.5-1,
=11.5;
(3)
×[
-(
-
)],
=
×[
-
+
],
=
×[
+
-
],
=
×[1-
],
=
×
,
=
;
(4)1÷[(
+
)÷
],
=1÷[
÷
],
=1÷
,
=
.
(1)32×125%×0.25,
=(4×8)×0.125×0.25,
=(8×0.125)×(4×0.25),
=1×1,
=1;
(2)12.5-0.625-
| 3 |
| 8 |
=12.5-(0.625+
| 3 |
| 8 |
=12.5-1,
=11.5;
(3)
| 4 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 4 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 4 |
| 9 |
| 3 |
| 4 |
| 1 |
| 4 |
| 7 |
| 16 |
=
| 4 |
| 9 |
| 7 |
| 16 |
=
| 4 |
| 9 |
| 9 |
| 16 |
=
| 1 |
| 4 |
(4)1÷[(
| 1 |
| 3 |
| 5 |
| 6 |
| 5 |
| 12 |
=1÷[
| 7 |
| 6 |
| 5 |
| 12 |
=1÷
| 14 |
| 5 |
=
| 5 |
| 14 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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