题目内容
(1+
)(1+
)(1+
)…(1+
)(1-
)(1-
)…(1-
).
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(1+
)(1+
)(1+
)…(1+
)(1-
)(1-
)…(1-
),
═[(1+
)(1-
)][(1+
)(1-
)]…[(1+
)(1-
)](1+
)
=1×1×…×1×
,
=
.
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═[(1+
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=1×1×…×1×
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=
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