题目内容
在横线里填上“+”或“-”.
+ +
|
- -
|
- -
| ||||||||||||||||||
+ +
|
+ +
|
+ +
|
分析:根据题意可知,可利用异分母分数加减法,把每个算式先通分,然后再根据每个算式填写“+”或“-”即可,
解答:解:
+
=
,
-
=
,
-
=
,
+
=
,
+
=
,
+
=
.
故答案为:+,-,-,+,+,+.
| 1 |
| 8 |
| 1 |
| 4 |
| 3 |
| 8 |
| 3 |
| 5 |
| 3 |
| 10 |
| 3 |
| 10 |
| 5 |
| 6 |
| 3 |
| 4 |
| 1 |
| 12 |
| 2 |
| 5 |
| 1 |
| 3 |
| 11 |
| 15 |
| 2 |
| 7 |
| 1 |
| 2 |
| 11 |
| 14 |
| 5 |
| 8 |
| 1 |
| 6 |
| 11 |
| 24 |
故答案为:+,-,-,+,+,+.
点评:此题主要考查的是异分母分数相加减的计算方法的灵活应用.
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