题目内容
计算:l+{[(l-0.9)2×10-0.09]×100-0.009}×(2×1
÷
-2
×3)=______.
| 1 |
| 5 |
| 3 |
| 10 |
| 2 |
| 3 |
l+{[(l-0.9)2×10-0.09]×100-0.009}×(2×1
÷
-2
×3)
=l+{[(l-0.9)2×10-0.09]×100-0.009}×(2×
×
-
×3)
=l+{[(l-0.9)2×10-0.09]×100-0.009}×(8-8)
=l+{[(l-0.9)2×10-0.09]×100-0.009}×0
=1;
故答案为:1.
| 1 |
| 5 |
| 3 |
| 10 |
| 2 |
| 3 |
=l+{[(l-0.9)2×10-0.09]×100-0.009}×(2×
| 6 |
| 5 |
| 10 |
| 3 |
| 8 |
| 3 |
=l+{[(l-0.9)2×10-0.09]×100-0.009}×(8-8)
=l+{[(l-0.9)2×10-0.09]×100-0.009}×0
=1;
故答案为:1.
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