题目内容
脱式计算.
6450-2600÷650×278
(512+2688÷56)×73
(9640-5230)÷(38+25)
6450-2600÷650×278
(512+2688÷56)×73
(9640-5230)÷(38+25)
分析:(1)可先计算算式中的除法,将278改写成300-22,然后依据乘法分配律进行解答,最后一步计算减法;
(2)将算式中的73改写成70+3,然后依据乘法分配律进行计算即可;
(3)直接按照整数的四则混合运算进行计算即可得到答案.
(2)将算式中的73改写成70+3,然后依据乘法分配律进行计算即可;
(3)直接按照整数的四则混合运算进行计算即可得到答案.
解答:解:(1)6450-2600÷650×278
=6450-[4×(300-22)],
=6450-[4×300-4×22],
=6450-[1200-88],
=6450-1112,
=5338;
(2)(512+2688÷56)×73
=(512+48)×73,
=560×(70+3),
=560×70+560×3,
=39200+1680,
=40880;
(3)(9640-5230)÷(38+25)
=4410÷63,
=70.
=6450-[4×(300-22)],
=6450-[4×300-4×22],
=6450-[1200-88],
=6450-1112,
=5338;
(2)(512+2688÷56)×73
=(512+48)×73,
=560×(70+3),
=560×70+560×3,
=39200+1680,
=40880;
(3)(9640-5230)÷(38+25)
=4410÷63,
=70.
点评:解答此题的关键是将算式中的数字进行改写,然后根据简便方法进行计算即可.
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