题目内容
(2012?中山模拟)解方程:
(1)(9+Χ):(9-Χ)=5:3
(2)x+(3x-16)÷25%=10(x+2)
(1)(9+Χ):(9-Χ)=5:3
(2)x+(3x-16)÷25%=10(x+2)
分析:(1)根据比例的意义,两内项之积等于两外项之积,然后去掉括号,再进一步解答即可;
(2)根据题意,先去掉括号,然后进一步解答即可.
(2)根据题意,先去掉括号,然后进一步解答即可.
解答:解:(1)(9+Χ):(9-Χ)=5:3,
3(9+X)=5(9-X),
3×9+3X=5×9-5X,
27+3X=45-5X,
3X+5X=45-27,
8X=18,
8X÷8=18÷8,
X=2.25;
(2)x+(3x-16)÷25%=10(x+2),
x+(3x-16)÷
=10x+10×2,
x+(3x-16)×4=10x+20,
x+3x×4-16×4=10x+20,
x+12x-64=10x+20,
x+12x-10x=20+64,
3x=84,
3x÷3=84÷3,
x=28.
3(9+X)=5(9-X),
3×9+3X=5×9-5X,
27+3X=45-5X,
3X+5X=45-27,
8X=18,
8X÷8=18÷8,
X=2.25;
(2)x+(3x-16)÷25%=10(x+2),
x+(3x-16)÷
| 1 |
| 4 |
x+(3x-16)×4=10x+20,
x+3x×4-16×4=10x+20,
x+12x-64=10x+20,
x+12x-10x=20+64,
3x=84,
3x÷3=84÷3,
x=28.
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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