题目内容
求未知数x的值.
|
|
分析:(1)根据除数=被除数÷商进行解答即可;
(2)根据被除数=商×除数即可;
(3)等式的两边同时减去
,然后等式的两边同时除以
即可.
(2)根据被除数=商×除数即可;
(3)等式的两边同时减去
| 1 |
| 5 |
| 5 |
| 8 |
解答:解:(1)
÷x=
,
x=
÷
,
x=
;
(2)x÷
=42,
x=42×
,
x=9;
(3)
x+
=
,
x+
-
=
-
,
x=
,
x÷
=
÷
,
x=
.
| 21 |
| 100 |
| 7 |
| 3 |
x=
| 21 |
| 100 |
| 7 |
| 3 |
x=
| 9 |
| 100 |
(2)x÷
| 3 |
| 14 |
x=42×
| 3 |
| 14 |
x=9;
(3)
| 5 |
| 8 |
| 1 |
| 5 |
| 19 |
| 20 |
| 5 |
| 8 |
| 1 |
| 5 |
| 1 |
| 5 |
| 19 |
| 20 |
| 1 |
| 5 |
| 5 |
| 8 |
| 3 |
| 4 |
| 5 |
| 8 |
| 5 |
| 8 |
| 3 |
| 4 |
| 5 |
| 8 |
x=
| 6 |
| 5 |
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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