题目内容
| 3 |
| 4 |
| 7 |
| 8 |
| 15 |
| 14 |
| 4 |
| 5 |
| 1 |
| 7 |
| 2 |
| 5 |
分析:(1)运用除法性质解答,
(2)运用乘法交换律解答.
(2)运用乘法交换律解答.
解答:解:(1)
÷
÷
=
÷(
×
)
=
÷
=
;
(2)
×
÷
=
÷
×
=2×
=
.
| 3 |
| 4 |
| 7 |
| 8 |
| 15 |
| 14 |
=
| 3 |
| 4 |
| 7 |
| 8 |
| 15 |
| 14 |
=
| 3 |
| 4 |
| 15 |
| 16 |
=
| 4 |
| 5 |
(2)
| 4 |
| 5 |
| 1 |
| 7 |
| 2 |
| 5 |
=
| 4 |
| 5 |
| 2 |
| 5 |
| 1 |
| 7 |
=2×
| 1 |
| 7 |
=
| 2 |
| 7 |
点评:正确运用简便方法解决问题,是本题考查知识点.
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