题目内容
脱式计算(能简便的要用简便方法计算)
(1)
|
(2)
|
(3)
| ||||||||||||||||||
(4)7-(
|
(5)
|
(6)
|
分析:(1)(2)(4)(5)依据分数四则运算计算顺序即可解答,
(3)依据减法性质解答,
(6)运用加法交换律和结合律解答.
(3)依据减法性质解答,
(6)运用加法交换律和结合律解答.
解答:解:(1)
+
+
,
=
+
,
=
;
(2)
+
-
,
=
+
,
=1;
(3)
+
-
,
=
-
,
=
;
(4)7-(
-
),
=7-
,
=6
;
(5)
-(
+
),
=
-
,
=
;
(6)
+
-
+
,
=(
-
)+(
+
),
=0+
,
=
.
| 1 |
| 6 |
| 1 |
| 5 |
| 1 |
| 3 |
=
| 11 |
| 30 |
| 1 |
| 3 |
=
| 7 |
| 10 |
(2)
| 7 |
| 12 |
| 1 |
| 6 |
| 1 |
| 4 |
=
| 3 |
| 4 |
| 1 |
| 4 |
=1;
(3)
| 8 |
| 11 |
| 7 |
| 15 |
| 8 |
| 15 |
=
| 8 |
| 11 |
| 1 |
| 15 |
=
| 109 |
| 165 |
(4)7-(
| 3 |
| 4 |
| 1 |
| 5 |
=7-
| 11 |
| 20 |
=6
| 9 |
| 20 |
(5)
| 4 |
| 5 |
| 4 |
| 15 |
| 1 |
| 3 |
=
| 4 |
| 5 |
| 9 |
| 15 |
=
| 1 |
| 5 |
(6)
| 4 |
| 7 |
| 5 |
| 21 |
| 4 |
| 7 |
| 2 |
| 21 |
=(
| 4 |
| 7 |
| 4 |
| 7 |
| 5 |
| 21 |
| 2 |
| 21 |
=0+
| 1 |
| 3 |
=
| 1 |
| 3 |
点评:本题考查知识点:(1)按照四则运算计算顺序正确进行计算,(2)正确运用简便算法解决问题.
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