题目内容
脱式计算,能简算的要简算.
÷[
×(
-
)]
36×(
+
-
)
24×
+51×
(0.4+
)÷(
-0.75)×0.5.
| 9 |
| 10 |
| 1 |
| 2 |
| 6 |
| 5 |
| 3 |
| 10 |
36×(
| 7 |
| 12 |
| 5 |
| 9 |
| 1 |
| 4 |
24×
| 51 |
| 43 |
| 19 |
| 43 |
(0.4+
| 2 |
| 3 |
| 5 |
| 6 |
分析:(1)先算小括号里面的减法,再算中括号的乘法,最后算括号外的除法;
(2)运用乘法分配律简算;
(3)先根据积不变性质,把24×
变成51×
,再运用乘法分配律简算;
(4)先同时运算小括号的加法和减法,再算除法,最后算乘法.
(2)运用乘法分配律简算;
(3)先根据积不变性质,把24×
| 51 |
| 43 |
| 24 |
| 43 |
(4)先同时运算小括号的加法和减法,再算除法,最后算乘法.
解答:解:(1)
÷[
×(
-
)],
=
÷[
×
],
=
÷
,
=2;
(2)36×(
+
-
),
=36×
+36×
-36×
,
=21+20-9,
=41-9,
=32;
(3)24×
+51×
,
=51×
+51×
,
=51×(
+
),
=51×1,
=51;
(4)(0.4+
)÷(
-0.75)×0.5,
=(
+
)÷(
-
)×0.5,
=
÷
×
,
=
×
,
=
.
| 9 |
| 10 |
| 1 |
| 2 |
| 6 |
| 5 |
| 3 |
| 10 |
=
| 9 |
| 10 |
| 1 |
| 2 |
| 9 |
| 10 |
=
| 9 |
| 10 |
| 9 |
| 20 |
=2;
(2)36×(
| 7 |
| 12 |
| 5 |
| 9 |
| 1 |
| 4 |
=36×
| 7 |
| 12 |
| 5 |
| 9 |
| 1 |
| 4 |
=21+20-9,
=41-9,
=32;
(3)24×
| 51 |
| 43 |
| 19 |
| 43 |
=51×
| 24 |
| 43 |
| 19 |
| 43 |
=51×(
| 24 |
| 43 |
| 19 |
| 43 |
=51×1,
=51;
(4)(0.4+
| 2 |
| 3 |
| 5 |
| 6 |
=(
| 2 |
| 5 |
| 2 |
| 3 |
| 5 |
| 6 |
| 3 |
| 4 |
=
| 16 |
| 15 |
| 1 |
| 12 |
| 1 |
| 2 |
=
| 64 |
| 5 |
| 1 |
| 2 |
=
| 32 |
| 5 |
点评:四则混合运算的顺序:1、如果是同一级运算,一般按从左往右依次进行计算;
2、如果既有加减、又有乘除法,先算乘除法、再算加减;
3、如果有括号,先算括号里面的;
4、如果符合运算定律,可以利用运算定律进行简算.
2、如果既有加减、又有乘除法,先算乘除法、再算加减;
3、如果有括号,先算括号里面的;
4、如果符合运算定律,可以利用运算定律进行简算.
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