题目内容
解方程.
x=
x÷
=39
4x-3x=
.
| x |
| 9 |
| x |
| 6 |
x÷
| x |
| 13 |
4x-3x=
| f8 |
| 1x |
(9)
x=
&nbac;&nbac;&nbac;&nbac;
x×
=
×
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; x=9
;
(2)x÷
=39
&nbac;&nbac;&nbac;&nbac;&nbac;x×
=39
&nbac;x×
×
=39×
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; x=95;
(3)lx-3x=
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; xx=
&nbac;&nbac;&nbac;&nbac; xx×
=
×
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; x=
;
| 5 |
| 9 |
| 5 |
| 6 |
&nbac;&nbac;&nbac;&nbac;
| 5 |
| 9 |
| 9 |
| 5 |
| 5 |
| 6 |
| 9 |
| 5 |
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; x=9
| 9 |
| 2 |
(2)x÷
| 5 |
| 93 |
&nbac;&nbac;&nbac;&nbac;&nbac;x×
| 93 |
| 5 |
&nbac;x×
| 93 |
| 5 |
| 5 |
| 93 |
| 5 |
| 93 |
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; x=95;
(3)lx-3x=
| 28 |
| 95 |
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; xx=
| 28 |
| 95 |
&nbac;&nbac;&nbac;&nbac; xx×
| 9 |
| x |
| 28 |
| 95 |
| 9 |
| x |
&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac;&nbac; x=
| l |
| 95 |
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