题目内容
计算下列各题.
(1)
+
-0.75
(2)3.5-1
+
(3)
×5.3+0.125×4.7
(4)
×[
×(
-
÷2)].
(1)
| 2 |
| 3 |
| 1 |
| 6 |
(2)3.5-1
| 2 |
| 3 |
| 1 |
| 6 |
(3)
| 1 |
| 8 |
(4)
| 8 |
| 9 |
| 5 |
| 16 |
| 7 |
| 16 |
| 1 |
| 4 |
分析:(1)把小数化为分数,通分计算;
(2)把小数化为分数,运用加法交换律简算;
(3)把分数化为小数,运用乘法分配律简算;
(4)先算小括号内的除法,再算小括号内的减法,原式变为
×[
×
],去括号约分计算.
(2)把小数化为分数,运用加法交换律简算;
(3)把分数化为小数,运用乘法分配律简算;
(4)先算小括号内的除法,再算小括号内的减法,原式变为
| 8 |
| 9 |
| 5 |
| 16 |
| 5 |
| 16 |
解答:解:(1)
+
-0.75,
=
+
-
,
=
;
(2)3.5-1
+
,
=3
-1
+
,
=(3
+
)-1
,
=3
-1
,
=2;
(3)
×5.3+0.125×4.7,
=0.125×5.3+0.125×4.7,
=0.125×(5.3+4.7),
=0.125×10,
=1.25;
(4)
×[
×(
-
÷2)],
=
×[
×(
-
)],
=
×[
×
],
=
×
×
,
=
.
| 2 |
| 3 |
| 1 |
| 6 |
=
| 2 |
| 3 |
| 1 |
| 6 |
| 3 |
| 4 |
=
| 1 |
| 12 |
(2)3.5-1
| 2 |
| 3 |
| 1 |
| 6 |
=3
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 6 |
=(3
| 1 |
| 2 |
| 1 |
| 6 |
| 2 |
| 3 |
=3
| 2 |
| 3 |
| 2 |
| 3 |
=2;
(3)
| 1 |
| 8 |
=0.125×5.3+0.125×4.7,
=0.125×(5.3+4.7),
=0.125×10,
=1.25;
(4)
| 8 |
| 9 |
| 5 |
| 16 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 8 |
| 9 |
| 5 |
| 16 |
| 7 |
| 16 |
| 1 |
| 8 |
=
| 8 |
| 9 |
| 5 |
| 16 |
| 5 |
| 16 |
=
| 8 |
| 9 |
| 5 |
| 16 |
| 5 |
| 16 |
=
| 25 |
| 288 |
点评:注意观察题目中数字构成的特点和规律,善于灵活运用运算定律或运算技巧,巧妙解答.
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