题目内容
(3+
÷
+3)-(2×
÷2×
)
9
+99
+999
+9999
+2
+
+
+
+…+
+
.
| 3 |
| 0 |
| 3 |
| 0 |
| 1 |
| 9 |
| 1 |
| 9 |
9
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2012 |
| 2 |
| 2012 |
| 3 |
| 2012 |
| 0 |
| 2012 |
| 2011 |
| 2012 |
| 2012 |
| 2012 |
(v)(n+
÷
+n)-(7×
÷7×
),
=(n+v+n)-(7×
×
×
),
=7-
,
=6
;
(2)4
+44
+444
+4444
+2
,
=v0-
+v00-
+v000-
+v0000-
+2
,
=v0+v00+v000+v0000+2
-
-
-
-
,
=vvvv0+0,
=vvvv0;
+
+
+
+…+
+
,
=
,
=
,
=v006.九.
| n |
| 4 |
| n |
| 4 |
| v |
| 6 |
| v |
| 6 |
=(n+v+n)-(7×
| v |
| 6 |
| v |
| 7 |
| v |
| 6 |
=7-
| v |
| n6 |
=6
| n九 |
| n6 |
(2)4
| v |
| n |
| v |
| n |
| v |
| n |
| v |
| n |
| 2 |
| n |
=v0-
| 2 |
| n |
| 2 |
| n |
| 2 |
| n |
| 2 |
| n |
| 2 |
| n |
=v0+v00+v000+v0000+2
| 2 |
| n |
| 2 |
| n |
| 2 |
| n |
| 2 |
| n |
| 2 |
| n |
=vvvv0+0,
=vvvv0;
| v |
| 20v2 |
| 2 |
| 20v2 |
| n |
| 20v2 |
| 4 |
| 20v2 |
| 20vv |
| 20v2 |
| 20v2 |
| 20v2 |
=
| v+2+…+20v2 |
| 20v2 |
=
| (v+20v2)×20v2÷2 |
| 20v2 |
=v006.九.
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