题目内容
用递等式计算.
| 20-12÷
| 8-
| ||||||||||||||
| 48048÷12+88 | 9÷(
| (1-0.8×
|
(1)
| 5 |
| 6 |
| 1 |
| 4 |
| 3 |
| 5 |
=
| 10 |
| 3 |
| 3 |
| 5 |
=2;
(2)20-12÷
| 4 |
| 5 |
=20-15,
=5;
(3)8-
| 2 |
| 3 |
| 1 |
| 4 |
| 4 |
| 3 |
=8-
| 8 |
| 3 |
| 4 |
| 3 |
=8-(
| 8 |
| 3 |
| 4 |
| 3 |
=8-4,
=4;
(4)48048÷12+88,
=4004+88,
=4092;
(5)9÷(
| 7 |
| 9 |
| 2 |
| 3 |
=9÷
| 1 |
| 9 |
=81×3,
=243;
(6)(1-0.8×
| 3 |
| 4 |
| 4 |
| 5 |
=(1-0.6)÷
| 4 |
| 5 |
=0.4÷
| 4 |
| 5 |
=0.5.
练习册系列答案
相关题目