题目内容
(2011?罗江县模拟)计算下面各题,怎样简便就怎样计算.
①15.28+
-(
+4.28)
②(
-
)÷(1÷25%-
)
③1
-[(3.62×
+6.38÷7
)×1.82-1
×0.82]
④(1-
)×
+
÷
.
①15.28+
| 12 |
| 37 |
| 25 |
| 37 |
②(
| 4 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
③1
| 2 |
| 3 |
| 2 |
| 15 |
| 1 |
| 2 |
| 1 |
| 3 |
④(1-
| 4 |
| 97 |
| 18 |
| 19 |
| 31 |
| 97 |
| 19 |
| 43 |
分析:①运用减法的性质以及加法交换律与结合律简算;
②把百分数化为分数,两个括号同时计算,最后算除法;
③先算小括号内的除法,再算小括号内的加法,然后算乘法,再算中括号内的减法,最后算减法;
④把除法改为乘法,先算小括号内的,原式变为
×
+
×
,然后把93拆为31×3,运用乘法分配律简算.
②把百分数化为分数,两个括号同时计算,最后算除法;
③先算小括号内的除法,再算小括号内的加法,然后算乘法,再算中括号内的减法,最后算减法;
④把除法改为乘法,先算小括号内的,原式变为
| 93 |
| 97 |
| 18 |
| 19 |
| 31 |
| 97 |
| 43 |
| 19 |
解答:解:①15.28+
-(
+4.28),
=15.28+
-
-4.28,
=15.28-4.28+(
-
),
=11-
,
=10
;
②(
-
)÷(1÷25%-
),
=
÷(1÷
-
),
=
÷(4-
),
=
÷
,
=
×
,
=
;
③1
-[(3.62×
+6.38÷7
)×1.82-1
×0.82],
=1
-[(3.62×
+6.38×
)],
=1
-[(3.62+6.38)×
],
=1
-[10×
],
=1
-1
,
=
;
④(1-
)×
+
÷
,
=(1-
)×
+
×
,
=
×
+
×
,
=
×
+
×
,
=
×(3×
+
),
=
×(
+
),
=
×
,
=
.
| 12 |
| 37 |
| 25 |
| 37 |
=15.28+
| 12 |
| 37 |
| 25 |
| 37 |
=15.28-4.28+(
| 12 |
| 37 |
| 25 |
| 37 |
=11-
| 13 |
| 37 |
=10
| 24 |
| 37 |
②(
| 4 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
=
| 5 |
| 6 |
| 1 |
| 4 |
| 1 |
| 4 |
=
| 5 |
| 6 |
| 1 |
| 4 |
=
| 5 |
| 6 |
| 15 |
| 4 |
=
| 5 |
| 6 |
| 4 |
| 15 |
=
| 2 |
| 9 |
③1
| 2 |
| 3 |
| 2 |
| 15 |
| 1 |
| 2 |
| 1 |
| 3 |
=1
| 2 |
| 3 |
| 2 |
| 15 |
| 2 |
| 15 |
=1
| 2 |
| 3 |
| 2 |
| 15 |
=1
| 2 |
| 3 |
| 2 |
| 15 |
=1
| 2 |
| 3 |
| 1 |
| 3 |
=
| 1 |
| 3 |
④(1-
| 4 |
| 97 |
| 18 |
| 19 |
| 31 |
| 97 |
| 19 |
| 43 |
=(1-
| 4 |
| 97 |
| 18 |
| 19 |
| 31 |
| 97 |
| 43 |
| 19 |
=
| 93 |
| 97 |
| 18 |
| 19 |
| 31 |
| 97 |
| 43 |
| 19 |
=
| 31×3 |
| 97 |
| 18 |
| 19 |
| 31 |
| 97 |
| 43 |
| 19 |
=
| 31 |
| 97 |
| 18 |
| 19 |
| 43 |
| 19 |
=
| 31 |
| 97 |
| 54 |
| 19 |
| 43 |
| 19 |
=
| 31 |
| 97 |
| 97 |
| 19 |
=
| 31 |
| 19 |
点评:此题考查了分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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