题目内容
解下列方程.
(1)
x÷
=12
(2)5x-3×
=
(3)x×5=100×
.
(1)
| 2 |
| 3 |
| 1 |
| 4 |
(2)5x-3×
| 5 |
| 21 |
| 5 |
| 7 |
(3)x×5=100×
| 3 |
| 4 |
分析:把方程左右两边同时加、减、乘或除以一个数,使方程左边只剩x,这时方程左右两边相等,再算出答案.
解答:解:(1)
x÷
=12 (2)5x-3×
=
(3)x×5=100×
x=12×
5x-
=
5x=75
x=3 5x=
+
x=75÷5
x=3÷
5x=
x=15
x=
x=
÷5
x=
故答案是x=
,x=
,x=15
| 2 |
| 3 |
| 1 |
| 4 |
| 5 |
| 21 |
| 5 |
| 7 |
| 3 |
| 4 |
| 2 |
| 3 |
| 1 |
| 4 |
| 5 |
| 7 |
| 5 |
| 7 |
| 2 |
| 3 |
| 5 |
| 7 |
| 5 |
| 7 |
x=3÷
| 2 |
| 3 |
| 10 |
| 7 |
x=
| 9 |
| 2 |
| 10 |
| 7 |
x=
| 2 |
| 7 |
故答案是x=
| 9 |
| 2 |
| 2 |
| 7 |
点评:求出解后,要验算答案是不是正确;同时还要注意在解方程时开头要写上解.
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