题目内容
计算:
(1)(1-
÷
)÷
(2)3-1.5×
-
.
(1)(1-
| 1 |
| 4 |
| 3 |
| 8 |
| 7 |
| 9 |
(2)3-1.5×
| 10 |
| 21 |
| 2 |
| 7 |
分析:(1)先算小括号里面的除法,再算减法,最后算括号外面的除法;
(2)先算乘法,再根据连减的性质进行计算.
(2)先算乘法,再根据连减的性质进行计算.
解答:解:
(1)(1-
÷
)÷
,
=(1-
)÷
,
=
×
,
=
;
(2)3-1.5×
-
=3-
-
,
=3-(
+
),
=3-1,
=2.
(1)(1-
| 1 |
| 4 |
| 3 |
| 8 |
| 7 |
| 9 |
=(1-
| 2 |
| 3 |
| 7 |
| 9 |
=
| 1 |
| 3 |
| 9 |
| 7 |
=
| 3 |
| 7 |
(2)3-1.5×
| 10 |
| 21 |
| 2 |
| 7 |
=3-
| 5 |
| 7 |
| 2 |
| 7 |
=3-(
| 5 |
| 7 |
| 2 |
| 7 |
=3-1,
=2.
点评:四则运算,先弄清运算顺序,然后再进一步计算,能简算的要简算.
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