题目内容
用简便方法计算.
24×
×
×21
÷7+
×
46×
11.58-(7
+1.58)
24×
| 2 |
| 7 |
| 5 |
| 72 |
| 8 |
| 13 |
| 1 |
| 7 |
| 6 |
| 13 |
46×
| 7 |
| 45 |
| 5 |
| 11 |
分析:(1)可根据乘法交换律交换因数的位置,然后再进行计算比较简便;
(2)将算式中
÷7改写为
×
,然后直接应用乘法分配律进行计算即可得到答案;
(3)将算式中46×
改写成(45+1)×
,然后再依据乘法分配律进行解答即可;
(4)一个数减去若干个数的和等于这个数分别减去这些数,结果不变.
(2)将算式中
| 8 |
| 13 |
| 8 |
| 13 |
| 1 |
| 7 |
(3)将算式中46×
| 7 |
| 45 |
| 7 |
| 45 |
(4)一个数减去若干个数的和等于这个数分别减去这些数,结果不变.
解答:解:(1)24×
×
×21
=21×
×24×
,
=6×
,
=10;
(2)
÷7+
×
=
×
+
×
,
=(
+
)×
,
=
×
,
=
;
(3)46×
=(45+1)×
,
=45×
+1×
,
=7+
,
=7
;
(4)11.58-(7
+1.58)
=11.58-1.58-7
,
=10-7
,
=2
.
| 2 |
| 7 |
| 5 |
| 72 |
=21×
| 2 |
| 7 |
| 5 |
| 72 |
=6×
| 5 |
| 3 |
=10;
(2)
| 8 |
| 13 |
| 1 |
| 7 |
| 6 |
| 13 |
=
| 8 |
| 13 |
| 1 |
| 7 |
| 1 |
| 7 |
| 6 |
| 13 |
=(
| 8 |
| 13 |
| 6 |
| 13 |
| 1 |
| 7 |
=
| 14 |
| 13 |
| 1 |
| 7 |
=
| 2 |
| 13 |
(3)46×
| 7 |
| 45 |
=(45+1)×
| 7 |
| 45 |
=45×
| 7 |
| 45 |
| 7 |
| 45 |
=7+
| 7 |
| 45 |
=7
| 7 |
| 45 |
(4)11.58-(7
| 5 |
| 11 |
=11.58-1.58-7
| 5 |
| 11 |
=10-7
| 5 |
| 11 |
=2
| 6 |
| 11 |
点评:此题主要考查的是乘法交换律、乘法分配律在分数计算中的应用和一个数减去若干个数的和等于这个数分别减去这些数,结果不变.
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