题目内容
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2.25:12=a:4 | 1.5:8=
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分析:(1)、(2)、(5)、(6)、(7)根根据比例的基本性质“两外项的积等于两内项的积”,先把比例改写成简易方程,再根据等式的性质解方程即可;
(3)根据分数除法、乘法的法则进行计算;
(4)利用乘法分配律a×c+b×c=c×(a+b)进行简算.
(3)根据分数除法、乘法的法则进行计算;
(4)利用乘法分配律a×c+b×c=c×(a+b)进行简算.
解答:解:(1)
:
=
:x,
x=
×
,
x=
,
x÷
=
÷
,
x=
;
(2)
:x=
:
,
x×
=
×
,
x=
,
x÷
=
÷
,
x=1
;
(3)
÷
×
,
=
×
×
,
=
;
(4)
×
+
×
,
=
×(
+
),
=
×1,
=
;
(5)
:
=
:x,
×x=
×
,
x=
,
x÷
=
÷
,
x=
;
(6)2.25:12=a:4,
12×a=2.25×4,
12a=9,
12a÷12=9÷12,
a=
;
(7)1.5:8=
,
8×x=1.5×0.8,
8x=1.2,
8x÷8=1.2÷8,
x=0.15.
| 1 |
| 3 |
| 1 |
| 20 |
| 7 |
| 9 |
| 1 |
| 3 |
| 1 |
| 20 |
| 7 |
| 9 |
| 1 |
| 3 |
| 7 |
| 180 |
| 1 |
| 3 |
| 1 |
| 3 |
| 7 |
| 180 |
| 1 |
| 3 |
x=
| 7 |
| 60 |
(2)
| 1 |
| 2 |
| 1 |
| 6 |
| 3 |
| 5 |
x×
| 1 |
| 6 |
| 1 |
| 2 |
| 3 |
| 5 |
| 1 |
| 6 |
| 3 |
| 10 |
| 1 |
| 6 |
| 1 |
| 6 |
| 3 |
| 10 |
| 1 |
| 6 |
x=1
| 4 |
| 5 |
(3)
| 5 |
| 7 |
| 9 |
| 14 |
| 4 |
| 5 |
=
| 5 |
| 7 |
| 14 |
| 9 |
| 4 |
| 5 |
=
| 8 |
| 9 |
(4)
| 7 |
| 18 |
| 2 |
| 5 |
| 3 |
| 5 |
| 7 |
| 18 |
=
| 7 |
| 18 |
| 2 |
| 5 |
| 3 |
| 5 |
=
| 7 |
| 18 |
=
| 7 |
| 18 |
(5)
| 5 |
| 6 |
| 2 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
| 2 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
| 1 |
| 2 |
| 5 |
| 6 |
| 5 |
| 6 |
| 1 |
| 2 |
| 5 |
| 6 |
x=
| 3 |
| 5 |
(6)2.25:12=a:4,
12×a=2.25×4,
12a=9,
12a÷12=9÷12,
a=
| 3 |
| 4 |
(7)1.5:8=
| x |
| 0.8 |
8×x=1.5×0.8,
8x=1.2,
8x÷8=1.2÷8,
x=0.15.
点评:此题考查了利用比例的性质及等式的性质解比例,注意在计算四则混合运算题目时要灵活运用运算定律使计算简便.
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