题目内容
用递等式计算,能巧算的要巧算.
5196-196×3
1830-44-756
56÷8×20
873-73×6
49÷7+360
7×140+60.
5196-196×3
1830-44-756
56÷8×20
873-73×6
49÷7+360
7×140+60.
分析:(1)(4)(5)(6)按照先算乘法,再算减法顺序即可解答,
(2)依据减法性质即可解答,
(3)按照从左到右顺序即可解答.
(2)依据减法性质即可解答,
(3)按照从左到右顺序即可解答.
解答:解:(1)5196-196×3,
=5196-588,
=4608;
(2)1830-44-756,
=1830-(44+756),
=1830-800,
=1030;
(3)56÷8×20,
=7×20,
=140;
(4)873-73×6,
=873-438,
=435;
(5)49÷7+360,
=7+360,
=367;
(6)7×140+60,
=980+60,
=1040.
=5196-588,
=4608;
(2)1830-44-756,
=1830-(44+756),
=1830-800,
=1030;
(3)56÷8×20,
=7×20,
=140;
(4)873-73×6,
=873-438,
=435;
(5)49÷7+360,
=7+360,
=367;
(6)7×140+60,
=980+60,
=1040.
点评:本题考查知识点:(1)依据四则运算顺序正确进行计算,(2)正确运用简便方法解决问题.
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