题目内容

用递等式计算.
(1)201-28.4×6.5
(2)(1-
1
22
)×(1-
1
32
)×(1-
1
42
(3)2.5-(0.65+0.35÷
5
12
(4)0.9-75÷90+
1
6
(5)3-
6
7
÷(
4
5
-0.38)
(6)2.5(4+x)-2.5x
(1)201-28.4×6.5,
=201-184.6,
=16.4;

(2)(1-
1
22
)×(1-
1
32
)×(1-
1
42
),
=(1-
1
4
)×(1-
1
9
)×(1-
1
16
),
=
3
4
×
8
9
×
15
16

=
2
3
×
15
16

=
5
8


(3)2.5-(0.65+0.35÷
5
12
),
=2.5-(0.65+0.84),
=2.5-1.49,
=1.01;

(4)0.9-75÷90+
1
6

=0.9-
5
6
+
1
6

=
9
10
-(
5
6
-
1
6
),
=
9
10
-
2
3

=
7
30


(5)3-
6
7
÷(
4
5
-0.38),
=3-
6
7
÷
21
50

=3-
100
49

=
47
49


(6)2.5×(4+x)-2.5x,
=2.5×4+2.5x-2.5x,
=10+(2.5x-2.5x),
=10+0,
=10.
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