题目内容
把下面九个分数填在横线里,使得每组三个数的和相等:
,
,
,
,
,
,
,
,
+
+
=
+
+
=
+
+
.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
| 5 |
| 12 |
| 7 |
| 12 |
| 1 |
| 2 |
| 1 |
| 2 |
| 7 |
| 12 |
| 7 |
| 12 |
| 1 |
| 6 |
| 1 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 12 |
| 1 |
| 12 |
| 3 |
| 4 |
| 3 |
| 4 |
| 5 |
| 12 |
| 5 |
| 12 |
分析:根据题意,可先别这九个分数通分,通分后,分母都是12,分子从小到大排列为:1、2、3、4、5、6、7、8、9,所以根据分数加法的计算方法,只要使三个分数分子相加的和是15即可.
解答:解:
=
,
=
,
=
,
=
,
=
,
=
,
通分后的分数为:
,
,
,
,
,
,
,
,
,
+
+
=
+
+
=
+
+
,即
+
+
=
+
+
=
+
+
.
故答案为:
,
,
,
,
,
,
,
,
.
| 1 |
| 2 |
| 6 |
| 12 |
| 1 |
| 3 |
| 4 |
| 12 |
| 1 |
| 4 |
| 3 |
| 12 |
| 1 |
| 6 |
| 2 |
| 12 |
| 2 |
| 3 |
| 8 |
| 12 |
| 3 |
| 4 |
| 9 |
| 12 |
通分后的分数为:
| 6 |
| 12 |
| 4 |
| 12 |
| 3 |
| 12 |
| 2 |
| 12 |
| 1 |
| 12 |
| 8 |
| 12 |
| 9 |
| 12 |
| 5 |
| 12 |
| 7 |
| 12 |
| 6 |
| 12 |
| 7 |
| 12 |
| 2 |
| 12 |
| 8 |
| 12 |
| 4 |
| 12 |
| 3 |
| 12 |
| 1 |
| 12 |
| 9 |
| 12 |
| 5 |
| 12 |
| 1 |
| 2 |
| 7 |
| 12 |
| 1 |
| 6 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 12 |
| 3 |
| 4 |
| 5 |
| 12 |
故答案为:
| 1 |
| 2 |
| 7 |
| 12 |
| 1 |
| 6 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 12 |
| 3 |
| 4 |
| 5 |
| 12 |
点评:解答此题的关键是先通分,然后再根据分子的特点,然后再利用分数加法的计算方法进行计算即可.
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