题目内容
甲数=4321×1234 乙数=4322×1233 那么甲数( )乙数.
分析:分别把4322变成(4321+1),1234变成(1233+1),再根据乘法分配律,进行运算,据此解答.
解答:解:甲数=4321×1234,
=4321×(1233+1),
=4321×1233+4321,
乙数=4322×1233,
=(4321+1)×1233,
=4321×1233+1233;
4321×1233+4321>4321×1233+1233,
即甲数>乙数;
故答案为:A.
=4321×(1233+1),
=4321×1233+4321,
乙数=4322×1233,
=(4321+1)×1233,
=4321×1233+1233;
4321×1233+4321>4321×1233+1233,
即甲数>乙数;
故答案为:A.
点评:本题考查了学生灵活运用乘法分配律的能力.
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