题目内容
用递等式计算.
+
+
1-
-
1367+247×6
(1200-1137)÷9.
| 7 |
| 15 |
| 4 |
| 15 |
| 1 |
| 5 |
1-
| 1 |
| 9 |
| 4 |
| 9 |
1367+247×6
(1200-1137)÷9.
分析:(1)按照从左到右顺序解答,
(2)运用减法性质解答,
(3)按照先算乘法,再算加法顺序解答,
(4)按照先算括号里面的减法,再算括号外面的除法顺序解答.
(2)运用减法性质解答,
(3)按照先算乘法,再算加法顺序解答,
(4)按照先算括号里面的减法,再算括号外面的除法顺序解答.
解答:解:(1)
+
+
=
+
=
;
(2)1-
-
=1-(
+
)
=1-
=
;
(3)1367+247×6
=1367+1482
=2849;
(4)(1200-1137)÷9
=63÷9
=7.
| 7 |
| 15 |
| 4 |
| 15 |
| 1 |
| 5 |
=
| 11 |
| 15 |
| 1 |
| 5 |
=
| 14 |
| 15 |
(2)1-
| 1 |
| 9 |
| 4 |
| 9 |
=1-(
| 1 |
| 9 |
| 4 |
| 9 |
=1-
| 5 |
| 9 |
=
| 4 |
| 9 |
(3)1367+247×6
=1367+1482
=2849;
(4)(1200-1137)÷9
=63÷9
=7.
点评:本题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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