题目内容
解方程.
(1)(1-25%)x=72
(2)x-40%x=5.04
(3)x÷(1-40%)=3.6
(4)34x-25%x=12.
(1)(1-25%)x=72
(2)x-40%x=5.04
(3)x÷(1-40%)=3.6
(4)34x-25%x=12.
分析:(1)先化简方程,再依据等式的性质,方程两边同时除以75%求解,
(2)先化简方程,再依据等式的性质,方程两边同时除以60%求解,
(3)先化简方程,再依据等式的性质,方程两边同时乘60%求解,
(4)先化简方程,再依据等式的性质,方程两边同时除以33.75求解.
(2)先化简方程,再依据等式的性质,方程两边同时除以60%求解,
(3)先化简方程,再依据等式的性质,方程两边同时乘60%求解,
(4)先化简方程,再依据等式的性质,方程两边同时除以33.75求解.
解答:解:(1)(1-25%)x=72,
75%x=72,
75%x÷75%=72÷75%,
x=96;
(2)x-40%x=5.04,
60%x=5.04,
60%x÷60%=5.04÷60%,
x=8.4;
(3)x÷(1-40%)=3.6,
x÷60%=3.6,
x÷60%×60%=3.6×60%,
x=2.16;
(4)34x-25%x=12,
33.75x=12,
33.75x÷33.75=12÷33.75,
x=
.
75%x=72,
75%x÷75%=72÷75%,
x=96;
(2)x-40%x=5.04,
60%x=5.04,
60%x÷60%=5.04÷60%,
x=8.4;
(3)x÷(1-40%)=3.6,
x÷60%=3.6,
x÷60%×60%=3.6×60%,
x=2.16;
(4)34x-25%x=12,
33.75x=12,
33.75x÷33.75=12÷33.75,
x=
| 16 |
| 45 |
点评:本题主要考查学生依据等式的性质解方程的能力,解方程时注意对齐等号.
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