题目内容
解方程. (1)60%X+25=40 |
(2)X+12.5%X=72 | ||
(3)75%X-
|
(4)X×(1-25%-20%)=550. |
分析:(1)依据等式的性质,方程两边同时减25,再同时除以60%求解,
(2)先化简方程,再依据等式的性质,方程两边同时除以1.125求解,
(3)依据等式的性质,方程两边同时加
,再同时减0.5x,最后同时除以0.25求解,
(4)先化简方程,再依据等式的性质,方程两边同时除以55%求解.
(2)先化简方程,再依据等式的性质,方程两边同时除以1.125求解,
(3)依据等式的性质,方程两边同时加
1 |
16 |
(4)先化简方程,再依据等式的性质,方程两边同时除以55%求解.
解答:解:(1)60%X+25=40,
60%X+25-25=40-25,
60%x=15,
60%x÷60%=15÷60%,
x=25;
(2)X+12.5%X=72,
1.125x=72,
1.125x÷1.125=72÷1.125,
x=64;
(3)75%X-
=0.5X,
75%X-
+
=0.5X+
,
75%x-0.5x=0.5x+
-0.5x,
0.25x=
,
0.25x÷0.25=
÷0.25,
x=
;
(4)X×(1-25%-20%)=550,
55%x=550,
55%x÷55%=550÷55%,
x=1000.
60%X+25-25=40-25,
60%x=15,
60%x÷60%=15÷60%,
x=25;
(2)X+12.5%X=72,
1.125x=72,
1.125x÷1.125=72÷1.125,
x=64;
(3)75%X-
1 |
16 |
75%X-
1 |
16 |
1 |
16 |
1 |
16 |
75%x-0.5x=0.5x+
1 |
16 |
0.25x=
1 |
16 |
0.25x÷0.25=
1 |
16 |
x=
1 |
4 |
(4)X×(1-25%-20%)=550,
55%x=550,
55%x÷55%=550÷55%,
x=1000.
点评:等式的性质是解方程的依据,解方程时注意:(1)方程能化简先化简,(2)对齐等号.
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