题目内容
7X÷
=
1-
X=
.
| 1 |
| 2 |
| 3 |
| 5 |
1-
| 1 |
| 5 |
| 4 |
| 5 |
分析:(1)根据等式的性质,在方程两边同时乘上
,再除以7求解,
(2)根据等式的性质,在方程两边同时加上
X,再减去
,最后乘上5求解.
| 1 |
| 2 |
(2)根据等式的性质,在方程两边同时加上
| 1 |
| 5 |
| 4 |
| 5 |
解答:解:(1)7X÷
=
,
7X÷
×
=
×
,
7X÷7=
÷7,
X=
;
(2)1-
X=
,
1-
X+
X=
+
X,
1-
=
+
X-
,
×5=
X×5,
X=1.
| 1 |
| 2 |
| 3 |
| 5 |
7X÷
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 5 |
| 1 |
| 2 |
7X÷7=
| 3 |
| 10 |
X=
| 3 |
| 70 |
(2)1-
| 1 |
| 5 |
| 4 |
| 5 |
1-
| 1 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
1-
| 4 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
| 1 |
| 5 |
X=1.
点评:本题考查了学生根据等式的性质解议程的能力,注意等号对齐.
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