题目内容
循环小数运算:
(1)0.
3
+0.
4
+0.
2
= ;
(2)0.
8
+0.
4
+0.
5
= ;
(3)0.
3
+0.3
+0.42
= ;
(4)0.1
+0.2
+0.3
+0.4
+0.5
+0.6
+0.7
+0.8
= .
(1)0.
| . |
| 2 |
| . |
| 4 |
| . |
| 3 |
| . |
| 2 |
| . |
| 4 |
| . |
| 3 |
(2)0.
| . |
| 7 |
| . |
| 9 |
| . |
| 6 |
| . |
| 3 |
| . |
| 5 |
| . |
| 7 |
(3)0.
| . |
| 2 |
| . |
| 4 |
| . |
| 4 |
| . |
| 2 |
| . |
| 3 |
(4)0.1
| . |
| 2 |
| . |
| 3 |
| . |
| 4 |
| . |
| 5 |
| . |
| 6 |
| . |
| 7 |
| . |
| 8 |
| . |
| 9 |
考点:循环小数及其分类
专题:运算顺序及法则
分析:先把循环小数化为分数,然后再进行计算即可:纯循环小数化成分数,循环节有几个数字,分母就有几个9,分子是循环节的数字;混循环小数化成分数,循环节有几个数字,分母就有几个9,循环节前到小数点间有几位数字,分母9后面就有几个0,分子是混循环数字减去循环节前数字的差,有些化成的分数需要约分.
解答:
解:(1)0.
3
+0.
4
+0.
2
=
+
+
=
=1
(2)0.
8
+0.
4
+0.
5
=
+
+
=
=1.
9
(3)0.
3
+0.3
+0.42
=
+
+
=1
(4)0.1
+0.2
+0.3
+0.4
+0.5
+0.6
+0.7
+0.8
=
+
+
+
+
+
+
+
=4
| . |
| 2 |
| . |
| 4 |
| . |
| 3 |
| . |
| 2 |
| . |
| 4 |
| . |
| 3 |
=
| 234 |
| 999 |
| 342 |
| 999 |
| 423 |
| 999 |
=
| 999 |
| 999 |
=1
(2)0.
| . |
| 7 |
| . |
| 9 |
| . |
| 6 |
| . |
| 3 |
| . |
| 5 |
| . |
| 7 |
=
| 789 |
| 999 |
| 643 |
| 999 |
| 557 |
| 999 |
=
| 1989 |
| 999 |
=1.
| ? |
| 9 |
| ? |
| 0 |
(3)0.
| . |
| 2 |
| . |
| 4 |
| . |
| 4 |
| . |
| 2 |
| ? |
| 3 |
=
| 234 |
| 999 |
| 342 |
| 999 |
| 423 |
| 999 |
=1
(4)0.1
| . |
| 2 |
| . |
| 3 |
| . |
| 4 |
| . |
| 5 |
| . |
| 6 |
| . |
| 7 |
| . |
| 8 |
| . |
| 9 |
=
| 12-1 |
| 90 |
| 23-2 |
| 90 |
| 34-3 |
| 90 |
| 45-4 |
| 90 |
| 56-5 |
| 90 |
| 67-6 |
| 90 |
| 78-7 |
| 90 |
| 89-8 |
| 90 |
=4
| 4 |
| 45 |
点评:此题主要考查的是循环小数化成分数的方法.
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