题目内容
计算:(1)1÷(1-
)÷(1-
)÷(1-
)÷…÷(1-
).
(2)(1-
)×(1+
)×(1-
)×(1+
)×(1-
)×(1+
).
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 10 |
(2)(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
分析:(1)先求出每个括号内的结果,然后把除法改为乘法,通过约分计算即可;
(2)先求出每个括号内的结果,除了第一项和最后一项,中间部分通过约分结果为1,算式只剩下
×
,计算即可.
(2)先求出每个括号内的结果,除了第一项和最后一项,中间部分通过约分结果为1,算式只剩下
| 1 |
| 2 |
| 5 |
| 4 |
解答:解:(1)1÷(1-
)÷(1-
)÷(1-
)÷…÷(1-
),
=1÷
÷
÷
÷…÷
,
=1×
×
×
×…×
,
=
×10,
=
;
(2)(1-
)×(1+
)×(1-
)×(1+
)×(1-
)×(1+
),
=
×
×
×
×
×
,
=
×
,
=
.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 10 |
=1÷
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 4 |
| 9 |
| 10 |
=1×
| 1 |
| 2 |
| 3 |
| 2 |
| 4 |
| 3 |
| 10 |
| 9 |
=
| 1 |
| 4 |
=
| 5 |
| 2 |
(2)(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
=
| 1 |
| 2 |
| 3 |
| 2 |
| 2 |
| 3 |
| 4 |
| 3 |
| 3 |
| 4 |
| 5 |
| 4 |
=
| 1 |
| 2 |
| 5 |
| 4 |
=
| 5 |
| 8 |
点评:完成此题,应仔细分析数据,采用约分的方法,简算得出结果.
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