题目内容
递等式计算.
×25%+
×
; 1+(40%+
)×
; 20×50%×
; (
-
)×
÷25%.
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考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)利用乘法分配律简算;
(2)先算括号里面的加法,再算乘法,最后算加法;
(3)把百分数化为分数,约分计算;
(4)先算减法,再算乘法,最后算除法.
(2)先算括号里面的加法,再算乘法,最后算加法;
(3)把百分数化为分数,约分计算;
(4)先算减法,再算乘法,最后算除法.
解答:
解:(1)
×25%+
×
=(
+
)×
=
×
=
;
(2)1+(40%+
)×
=1+1×
=1+
=
;
(3)20×50%×
=20×
×
=
;
(4)(
-
)×
÷25%
=
×
×4
=
.
| 3 |
| 5 |
| 1 |
| 4 |
| 4 |
| 5 |
=(
| 3 |
| 5 |
| 4 |
| 5 |
| 1 |
| 4 |
=
| 7 |
| 5 |
| 1 |
| 4 |
=
| 7 |
| 20 |
(2)1+(40%+
| 3 |
| 5 |
| 1 |
| 6 |
=1+1×
| 1 |
| 6 |
=1+
| 1 |
| 6 |
=
| 7 |
| 6 |
(3)20×50%×
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| 6 |
=20×
| 1 |
| 2 |
| 5 |
| 6 |
=
| 25 |
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(4)(
| 1 |
| 2 |
| 1 |
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| 3 |
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=
| 1 |
| 6 |
| 3 |
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=
| 1 |
| 2 |
点评:分数混合运算的关键是抓住运算顺序,正确按运算顺序计算,适当利用运算定律简算.
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