题目内容
在下面的数字之间添上运算符号或括号,使等式成立.
1
1
1
1
+
+
2÷
÷
3=11
×
×
2+
+
3-
-
4=11
+
+
2×
×
3-
-
4÷
÷
5=1.分析:(1)因为1+2=3,3÷3=1;据此解答即可;
(2)因为1×2=2,2+3=5,5-4=1;据此解答;
(3)1+2=3,3×3=9,9-4=5,5÷5=1;据此解答.
(2)因为1×2=2,2+3=5,5-4=1;据此解答;
(3)1+2=3,3×3=9,9-4=5,5÷5=1;据此解答.
解答:解:(1)(1+2)÷3,
=3÷3,
=1;
(2)1×2+3-4,
=2+3-4,
=1;
(3)[(1+2)×3-4]÷5,
=[9-4]÷5,
=1;
故答案为:(+),÷;×,+,-;[(+),×,-],÷.
=3÷3,
=1;
(2)1×2+3-4,
=2+3-4,
=1;
(3)[(1+2)×3-4]÷5,
=[9-4]÷5,
=1;
故答案为:(+),÷;×,+,-;[(+),×,-],÷.
点评:观察题干,综合分析数字以及运算符号的特点进行解答.
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