题目内容
(2012?安徽模拟)怎样算简便就怎样算.
[(
-
)+
-
]÷
34×(
+
)×13
[1-(
-
)]×
1375+450÷18×25.
[(
| 14 |
| 19 |
| 5 |
| 13 |
| 5 |
| 19 |
| 8 |
| 13 |
| 11 |
| 12 |
34×(
| 1 |
| 17 |
| 1 |
| 13 |
[1-(
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 3 |
1375+450÷18×25.
分析:(1)在中括号中,先去小括号,运用加法交换律与结合律简算,中括号内的结果为0,因此最终结果为0;
(2)根据数字特点,运用乘法分配律简算;
(3)按运算顺序进行计算,先算小括号内的,再算中括号内的,最后算括号外的;
(4)此题含有两级运算,先算除法和乘法,再算加法.
(2)根据数字特点,运用乘法分配律简算;
(3)按运算顺序进行计算,先算小括号内的,再算中括号内的,最后算括号外的;
(4)此题含有两级运算,先算除法和乘法,再算加法.
解答:解:(1)[(
-
)+
-
]÷
,
=[
-
+
-
]÷
,
=[
+
-(
+
)]÷
,
=[1-1]÷
,
=0;
(2)34×(
+
)×13,
=34×
×13+34×
×13,
=26+34,
=60;
(3)[1-(
-
)]×
,
=[1-
]×
,
=
×
,
=
;
(4)1375+450÷18×25,
=1375+25×25,
=1375+625,
=2000.
| 14 |
| 19 |
| 5 |
| 13 |
| 5 |
| 19 |
| 8 |
| 13 |
| 11 |
| 12 |
=[
| 14 |
| 19 |
| 5 |
| 13 |
| 5 |
| 19 |
| 8 |
| 13 |
| 11 |
| 12 |
=[
| 14 |
| 19 |
| 5 |
| 19 |
| 5 |
| 13 |
| 8 |
| 13 |
| 11 |
| 12 |
=[1-1]÷
| 11 |
| 12 |
=0;
(2)34×(
| 1 |
| 17 |
| 1 |
| 13 |
=34×
| 1 |
| 17 |
| 1 |
| 13 |
=26+34,
=60;
(3)[1-(
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 3 |
=[1-
| 1 |
| 4 |
| 2 |
| 3 |
=
| 3 |
| 4 |
| 2 |
| 3 |
=
| 1 |
| 2 |
(4)1375+450÷18×25,
=1375+25×25,
=1375+625,
=2000.
点评:此题考查了学生对运算顺序的掌握,以及对运算定律或性质的运用情况.
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