题目内容
计算:51
÷
+71
÷
-91
×
.
| 2 |
| 3 |
| 5 |
| 3 |
| 3 |
| 4 |
| 7 |
| 4 |
| 4 |
| 5 |
| 5 |
| 9 |
分析:把算式中的除法先变成乘法就会发现:每两个相乘的数中第一个因数都是第二个因数的分母的10倍多一些;所以把第一个因数分解成一个整数的数加一个分数,然后再运用乘法分配律求解.
解答:解:51
÷
+71
÷
-91
×
,
=51
×
+71
×
-91
×
,
=(50+
)×
+(70+
)×
-(90+
)×
,
=[50×
+
×
]+[70×
+
×
]-[90×
+
×
],
=[30+1]+[40+1]-[50+1],
=31+41-51,
=72-51,
=21.
| 2 |
| 3 |
| 5 |
| 3 |
| 3 |
| 4 |
| 7 |
| 4 |
| 4 |
| 5 |
| 5 |
| 9 |
=51
| 2 |
| 3 |
| 3 |
| 5 |
| 3 |
| 4 |
| 4 |
| 7 |
| 4 |
| 5 |
| 5 |
| 9 |
=(50+
| 5 |
| 3 |
| 3 |
| 5 |
| 7 |
| 4 |
| 4 |
| 7 |
| 9 |
| 5 |
| 5 |
| 9 |
=[50×
| 3 |
| 5 |
| 5 |
| 3 |
| 3 |
| 5 |
| 4 |
| 7 |
| 7 |
| 4 |
| 4 |
| 7 |
| 5 |
| 9 |
| 9 |
| 5 |
| 5 |
| 9 |
=[30+1]+[40+1]-[50+1],
=31+41-51,
=72-51,
=21.
点评:本题解答的关键是发现第一个因数分解的方法,进而运用乘法分配律求解.
练习册系列答案
相关题目