题目内容
如果3a-2b=
,那么
a-b=______,
-(3a-2b)+
=______.
| 7 |
| 9 |
| 3 |
| 2 |
| 7 |
| 6 |
| 1 |
| 3 |
(1)因为3a-2b=
,
所以3a=
+2b,
a=(
+2b)×
,
a=
b+
,
把a=
b+
代入式子
a-b中,
原式=
×(
b+
)-b,
=b+
-b,
=
;
(2)把3a-2b=
代入
-(3a-2b)+
中,
原式=
-
+
,
=
-
+
,
=
;
故答案为:
,
.
| 7 |
| 9 |
所以3a=
| 7 |
| 9 |
a=(
| 7 |
| 9 |
| 1 |
| 3 |
a=
| 2 |
| 3 |
| 7 |
| 27 |
把a=
| 2 |
| 3 |
| 7 |
| 27 |
| 3 |
| 2 |
原式=
| 3 |
| 2 |
| 2 |
| 3 |
| 7 |
| 27 |
=b+
| 7 |
| 18 |
=
| 7 |
| 18 |
(2)把3a-2b=
| 7 |
| 9 |
| 7 |
| 6 |
| 1 |
| 3 |
原式=
| 7 |
| 6 |
| 7 |
| 9 |
| 1 |
| 3 |
=
| 21 |
| 18 |
| 14 |
| 18 |
| 6 |
| 18 |
=
| 13 |
| 18 |
故答案为:
| 7 |
| 9 |
| 13 |
| 18 |
练习册系列答案
相关题目